#### riddle.

8.- The problem is basically the same as the previous 12 coins, just do not know if the false coin weighs more or less, and still have only three weighed on a scale.

The question is what is the counterfeit money and if you weigh more or less than others

#### Solution

1 | < 1-2-3-4 >°< 5-6-7-8 > | ||||||||

A+ | Igual. | B+ | |||||||

2 | < 1-2-5-6 >°< 7-9-10-11 > | < 9-10 >°< 11-1 > | < 1-2-5-6 >°< 7-9-10-11 > | ||||||

A+ | Igual. | B+ | A+ | Igual. | B+ | A+ | Igual. | B+ | |

3 | < 1 >°< 2 > | < 3 >°< 4 > | < 5 >°< 6 > | < 9 >°< 10 > | < 12 >°< 1 > | < 9 >°< 10 > | < 5 >°< 6 > | < 3 >°< 4 > | < 1 >°< 2 > |

A+ -> 1+ = ---> 7- B+ -> 2+ |
A+ -> 3+ = ---> 8- B+ -> 4+ |
A+ -> 6- = ---> B+ -> 5- |
A+ -> 9+ = ---> 11- B+ -> 10+ |
A+ -> 12+ = ---> B+ -> 12- |
A+ -> 10- = ---> 11+ B+ -> 9- |
A+ -> 5+ = ---> B+ -> 6+ |
A+ -> 4- = ---> 8+ B+ -> 3- |
A+ -> 2- = ---> 7+ B+ -> 1- |

= balanced scale. % unbalanced balance. A+ heavier left pan. B+ heavier right dish. |
As you can see the second and third weighing are the same in the event that the balance lean to one side or another , is separated to clarify the explanation. |